ajay covers a distance of 240 km in 17/4 hours.some part of the journey was covered at a speed of 45 kmph and the rest by 60 kmph . find the distance he covered in 60 mph
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Speed= D/T
Let distance covered with speed 45kmph be x and 60kmph be y
D= S×T
T=D/S
240= 45x + 60y— eq 1
17/4= x/45 + y/60—eq 2
for sake of convenience, multiply eq 2 by 180 then by 20.
765= 4x + 3y
15300= 80x + 60y
subtract eq 1 from 2
15300= 80x + 60y
(-)240= 45x + 60y
15060= 35x
x= 15060/35
x= 430
substitute value of x in eq to find y.
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