Math, asked by shajarun9700, 1 year ago

Ajay covers a distance of 35 km in 3 hours more than the time taken by Vijay to cover the same distance by doubling his speed that takes 2 hours less than visit to cover the same distance find their speeds of walking

Answers

Answered by santy2
3

Answer:

Ajay = 3.5 km/h

Vijay = 5 km/h

Step-by-step explanation:

Let Ajay's speed be x.

Time = Distance / Speed

Time taken by Ajay = 35/x

This time is 3 hours more than the time taken by Vijay.

Time by Vijay = 35/x - 3

If Ajay doubles his speed the time taken is:

35/2x

This time is 2 hours less than the time taken by Vijay.

Time by Vijay = 35/2x + 2

Speed of Vijay is given by :

35/(35/x - 3) or 35/(35/2x + 2)

Since the speed of Vijay remains the same in both cases we have :

35/(35/x - 3) = 35/(35/2x + 2)

We now solve for x.

35(35/2x + 2) = 35(35/x - 3)

1225/2x + 70 = 1225/x - 105

70 + 105 = 1225/x - 1225/2x

175 = (1225 - 612.5)/x

175x = 612.5

x = 612.5/175

x = 3.5 km/h

Since we have x we can now get the speed of Vijay.

Speed of Vijay = 35/(35/x - 3)

= 35/(35/3.5 - 3)

= 35/(10 - 3) = 5 km/h

Ajay's speed = 3.5 km/h

Vijay's speed = 5 km/h

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