Question

Ajay deposit RS.25000 In a bank for 3 years at 10% per annum .find the compound interest at the end if the 3 years compounded annually​

Answer 1

Step-by-step explanation:

P = 25000

T = 3 years

R = 10%

A = P(1 + R/100)^t

A = 25000(1+10/100)³

A = 25000 × (11/10) × (11/10) × (11/10)

A = 33275

CI = A - P

CI = 33275 - 25000

CI = 8275

Answer 2

$\huge\mathfrak\color{aqua}QUESTION :-$

Ajay deposit RS.25000 In a bank for 3 years at 10% per annum .find the compound interest at the end if the 3 years compounded annually

$\sf\pink {\underline{\sf SOLUTION :-}}$

Given :

Principal (P) = Rs 25,000

Time (T) = 3 years

Rate (R) = 10% per annum

To Find :

Amount(A) = ?

Compound Interest (C.I.) = ?

Now,

Amount (A) = P (1+$\frac{R}{100}$${)}^{T}$

A = 25000×(1+$\frac{10}{100}$${)}^{3}$

A = 25000×(1+$\frac{11}{100}$${)}^{3}$

A = 25000×($\frac{11}{100}\frac{11}{100}\frac{11}{100}$)

A = 25000×($\frac{1331}{100}$)

A = 3,32,750

So,

Compound Interest(C.I) = Amount (A) - Principal(P)

C.I = 3,32750 - 25,000

C.I = Rs 3,07,750