Question

Ajay is painting the box of dimensions 10 cm × 11 cm × 9 cm if he Paints all surfaces except bottom find the area of face painted by him​

Answer 1

firstly find the L s a of the box

2(10+11)9

2*21*9

378

then add the bottom area

10*11

110

Answer 2

Answer: 488 cm. sq

Step-by-step explanation:

ajay is painting a box in the shape of cuboid .

first let us find the t.s.a and then subtract area of a side of cuboid from it

t.s.a = 2 (lb + bh + hl )

       = 2 { (10* 11 ) +(11*9) + (9*10 ) }

        =2{110 + 99 + 90 }

         = 2 *299

        = 598 cm sq

area of a side = area of rectangle = l*b

                                                        =10*11

                                                       =110cm.sq

the required area =598-110

                              =488 cm . sq