Question

Ajay is standing west to Varun at a distance of 1 km. Ajay starts walking in the north direction, whereas Varun starts walking in the north-west direction. Both meet after 20 minutes. The ratio of speed of Varun to that of Ajay is
(A) √2
(B) 1/√2
(C) 2
(D) 1/2

Answer 1

Answer:

Step-by-step explanation:

Answer 2

(A) √2

Step-by-step explanation:

Given that Ajay is to the west of Varun at a distance of 1km.

Ajay walks northwards, Varun walks towards north-west.

Time after which they meet after waking simultaneously, $t=20\ min$

The distance walked by Varun be d km.

Then the distance walked by Ajay will be, $d\times \cos 45^{\circ}\ km$

Now the ratio of their speeds:

$R=\frac{v_v}{v_a}$

where:

$v_v=$ speed of Varun

$v_a=$ speed of Ajay

$R=\frac{\frac{d}{t} }{(\frac{d\times \cos\ 45^{\circ}}{t}) }$

$R=\sqrt{2}$

#learnmore

TOPIC: speed distance time

https://brainly.com/question/10453468