Question

Ajay is thirteen years older than Aman. Thirty five years ago, Ajay was twice Aman's age. Find their present ages. * 1 point​

Answer 1

Answer:

search-icon-header

Search for questions & chapters

search-icon-image

Class 8

>>Maths

>>Linear Equations in One Variable

>>Solving Linear Equations with Variable on Both Sides

>>Aman's age is three times his son's age.

Question

Bookmark

Aman's age is three times his son's age. Ten years ago his age was five times his son's age. Find their present ages.

Medium

Solution

verified

Verified by Toppr

Correct option is C)

Hint: Use the given information to form a linear equation

Correct Option: C

Solution:

Step 1: Use the given information to form a linear equation

Let Aman's son's present age =x

According to the question, Aman's present age =3x

Given, ten years ago,

Aman's age =3x−10

Aman's son age =x−10

Aman's age =5 × Aman's son's age

∴3x−10=5(x−10)

Step 2: Solve the above equation

⇒3x−10=5x−50

⇒5x−3x=50−10

⇒2x=40

⇒x=20.

So, Aman's son's age =x=20 years

Aman's age =3x=3×20=60 years.

Therefore, the present ages of Aman and his son are 60 and 20 years.