Ajay’s mother is 6 times as old as Ajay. After 4 years, his mother will be 4 times Ajay’s age. Find their present ages
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Ajay’s current age is 6 and his mother’s age is 36
6*6=36 and after four years ajay will be 10 and then it will be 10*4=40 which is 36+4
Hope you understood.
6*6=36 and after four years ajay will be 10 and then it will be 10*4=40 which is 36+4
Hope you understood.
Answered by
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Let Ajays present age be x years
then her mother present age be 4x years
After 5 years Ajays age will be x+5 years
after 5 years Ajays mother age will be 4x+5
ACCORDING TO QUESTION
4x+5 = 3(x+5)
4x+5 = 3x + 15
4x-3x= 15-5
x=10
Ajays present age = 10 years
Ajays mother present age = 4x = 4×10 = 40 years
HOPE IT HELPS..
then her mother present age be 4x years
After 5 years Ajays age will be x+5 years
after 5 years Ajays mother age will be 4x+5
ACCORDING TO QUESTION
4x+5 = 3(x+5)
4x+5 = 3x + 15
4x-3x= 15-5
x=10
Ajays present age = 10 years
Ajays mother present age = 4x = 4×10 = 40 years
HOPE IT HELPS..
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