Math, asked by pikun229, 15 hours ago

Ajay saves 32% of his monthly income, while his friend Rohit saves 3/10 of his monthly income. Find who saved more, if the monthly incomes of Ajay and his friend is same. ​

Answers

Answered by yassersayeed
3

Given: Ajay saves 32% of his monthly income, and  Rohit saves\frac{3}{10} of his monthly income.

The monthly incomes of Ajay and Rohit are the same. ​

We have to find who saved more money.

The given problem is solved in the following way;

Let assume the monthly income of Ajay and Rohit is100rs.

Ajay saves 32% of his monthly income i.e;

=>\frac{32}{100} *100\\=>32

That means Ajay saves 32rs.

and Rohit saves\frac{3}{10} of his monthly income i.e;

=>100*\frac{3}{10} \\=>30

That means Rohit saves 30rs.

Hence, We can say that Ajay saves more money.

Answered by v8080shukla
0

Answer:

Step-by-step explanation:

Given: Ajay saves 32 % of his monthly income, and Rohit saves of his monthly income.

The monthly incomes of Ajay and Rohit

are the same. We have to find who saved more money.

The given problem is solved in the following way;

Let assume the monthly income of Ajay

and Rohit is 100rs.

Ajay saves 32 % of his monthly income i.e;

32/100 * 100

>32

That means Ajay saves 32rs.

and Rohit saves 3/10 of his monthly income i.e;

100 * => 3/10

=30

That means Ajay saves 32rs.

and Rohit saves of his monthly income 10 i.e;

100 * => 3/10

That means Rohit saves 30rs.

Hence, We can say that Ajay saves more money.

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