Question

Ajay sells two cycles at rs.2500 each of
he makes a profit of 25% on one, and
incurs a loss of 25% on the other,
Find his net profit on loss percent .​

Answer 1

Question

Ajay sells two cycles at rs.2500 each of

he makes a profit of 25% on one, and

incurs a loss of 25% on the other,

Find his net profit on loss percent.

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Answer

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Given

• Ajay sells two cycles at Rs.2500 each of he makes a profit of 25% on one,and incurs a loss of 25% on the other.

To Find

• His net profit on loss percent.

Solution

Ajay sold two cycles at Rs. 2500 each.

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25% profit on one cycle.

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: { \purple{\rightarrow \: {\bf{\purple {= \:2500\: × \: \frac{25}{100} = 625}}}}}$

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25% loss on one cycle .

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$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: { \purple{\rightarrow \: {\bf{\purple {= \:2500\: × \: \frac{25}{100} = 625}}}}}$

So,the profit amount = loss amount.

Hence,there is no profit or loss.

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Answer 2

Given:-

• Ajay sells two cycles of ₹2500 each.
• He makes a profit of 250%
• He incurs a loss of 25%

To Find:-

• Net Profit?
• Loss Percent?

Solution:-

S.P. of 1st cycle = ₹2500

Profit = 25%

So,

S.P. = CP $\tt (\dfrac{1 + x}{100})$

2500 = CP $\tt (\dfrac{1 + 25}{100})$

2500 = CP $\tt (\dfrac{125}{100})$

C.P. = $\tt \cancel\dfrac{2500 × 100}{125}$

C.P. = $\tt\dfrac{500 × 4}{1}$

C.P. = 2000/-

Loss = 25%

S.P. = C.P. $\tt(\dfrac{1 - x}{100})$

2500 = CP $\tt(\dfrac{1 - 25}{100})$

2500 = CP $\tt(\dfrac{125}{100})$

C.P. = $\tt\cancel\dfrac{2500 × 100}{75}$

= 3333.33 Rs.

So,

Total C.P. = 2000 + 3333.33

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Total S.P. = 2500 + 2500 = 5000

So,

Overall loss:-

= $\sf\dfrac{CP - SP}{CP} \times 100$

$\sf = \dfrac{5333.33 - 5000}{5333.33} \times 100$

= 6.25%

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Learn More:-

$\tt \: S.P. > C.P.$

$\tt \: Gain \: or \: Profit = Selling \: Price - Cost \: Price$

$\tt \: Gain\% = \dfrac{Gain} { CP} \times 100 \%$

$\tt \: Loss = C.P. - SP$

$\tt \: Loss \% = \dfrac{Loss} { CP} \times 100 \%$