Ajay start from his house to his office by his car which is 15 km away at an average speed of 45 km per hour . On the way back,he takes a route longer by 5km since there is heavy traffic on the regular route.if he reach home in the same time as the time he looked to reach office in the morning find his speed on the return journey ?
Answers
Answered by
1
Step-by-step explanation:
Difference in timing = 15 – (–20) = 35 min. Let required distance = x.
∴ x/10 - x15 = 35/60 → x = 17.5 km.
See this attachment..
Hope its help..
Attachments:
Similar questions