Question

Ajay starts chasing a thief. The speed of the Ajay and thief are 8km/h and 6km/h

respectively. If Ajay started 10 minutes late, at what distance he will catch the thief?​

Answer 1

Answer:

4 km

Explanation:

Assume after x minutes Ajay will be able to catch the thief.

speed of Thief = 6km/ hr = (6/60) km/min

Speed of Ajay = 8 km /hr = (8/60) km /min

At time x both must have travelled equal distance

note Ajay will be starting 10 minutes late so he will be running for (x-10) minutes.

$\frac{6}{60} \times x = \frac{8}{60} \times (x - 10)$

$6x = 8x - 80$

$8x - 6x = 80$

$2x = 80$

$x = 40$

After 40 minutes Ajay will be able to catch thief.

Distance covered by Ajay = (8/60)×(40-10) = 4 km