Math, asked by sparksha8308, 5 months ago

Ajay walks 8 km due east and then 15 km due north. How far is he from his starting place.

Answers

Answered by prashikwahane854
0

Step-by-step explanation:

Ajay walks 8km to east.

then he walks 15km to north.

So, by using the following Pythagoras rule we will find the answer:-

a²+b² = c²

⟹(8)²+(15)²

⟹64+225

⟹√289

⟹17KM

So, the distance from which ramesh started will be 17km.

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