Ajayan is ten years older than Vijayan Next
year, Ajayan's age would be double that of
Virayan. What are their ages now? solve this algebraic equations
Answers
Answered by
125
Answer:
Vijayan=9 year and Ajayan=19 year
Solution:-
Let vijayan age be x
Ajayan is ten years older than vijayan
So Ajayan age=x+10
Next year vijayan=x+1
And Ajayan=x+11 {as x+10+1}
Ajayan age would be double that of vijayan
So the equation
x+11=2(x+1)
x+11=2x+2
x-2x=2-11
-x=-9
x=9
--------
Vijayan age=x
=9 year
Ajayan age=x+10
=9+10
=19 year
Answered by
76
Answer:
Suppose the age of Vijayan = x
And The age of Ajayan's = ( X + 10 )
= X + 11 = 2( X + 1 )
= X + 11 = 2x + 3
= X - 2x = 2 - 11
= - X = - 9
X = 9
The age of Vijayan = X
= 9 years.
The age of Ajayan = X + 9
= 9 + 10 = 19 years
Similar questions
Math,
5 months ago
Business Studies,
5 months ago
Math,
10 months ago
Science,
10 months ago
Physics,
1 year ago