Math, asked by noufa34, 11 months ago

Ajayan is ten years older than Vijayan Next
year, Ajayan's age would be double that of
Virayan. What are their ages now? solve this algebraic equations ​

Answers

Answered by SnowySecret72
125

Answer:

Vijayan=9 year and Ajayan=19 year

Solution:-

Let vijayan age be x

Ajayan is ten years older than vijayan

So Ajayan age=x+10

Next year vijayan=x+1

And Ajayan=x+11 {as x+10+1}

Ajayan age would be double that of vijayan

So the equation

x+11=2(x+1)

x+11=2x+2

x-2x=2-11

-x=-9

x=9

--------

Vijayan age=x

=9 year

Ajayan age=x+10

=9+10

=19 year

Answered by ram5556
76

Answer:

Suppose the age of Vijayan = x

And The age of Ajayan's = ( X + 10 )

= X + 11 = 2( X + 1 )

= X + 11 = 2x + 3

= X - 2x = 2 - 11

= - X = - 9

X = 9

The age of Vijayan = X

= 9 years.

The age of Ajayan = X + 9

= 9 + 10 = 19 years

Similar questions