Math, asked by duhazakariyya, 7 months ago

Ajayan is ten years older than Vijayan. Next year, Ajayan's age would
be double that of Vijayan. What are their ages now?

Answers

Answered by pdhankhar2006
3

Answer:

Step-by-step explanation:

Let the age of Vijayan be x.

So the age of Ajayan = x + 10

After 1 year,

Age of Vijayan = x + 1

Age of Ajayan = x + 10 + 1

                        = x + 11

Now,

2(x+1) = x + 11

2x + 2 = x + 11

        x = 9

Therefore,

Age of Vijayan = x

                         = 9

Age of Ajayan = x + 10

                        = 9 + 10

                        = 19

Answered by ag0008699
4

Answer:

let the present age of vijayan be x years.

the the present age of ajayan is (x+10) years

next year

age of vijayan = (x+1)years

age of ajayan = (x+10+1) years

= (x +11) years

ATQ,

(x+1)2 = (x+11)

2x+2 = x+11

2x-x = 11-2

x = 9

hence the present age of vijayan = 9 years

and the present age of ajayan = (9+10) years

= 19 years

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