Question

ajit and ranjit went for a long walk of 24 kms the sum of their individual speeds is 10 kms/hr and the sum of their time taken by them is 10 hr. find how much faster is ajit from ranjit​

Answer 1

Answer:

Step-by-step explanation:

Let A's speed  = x  km/hr Then B's speed = (7 - x) km/hr So,  

x

24

​  

+  

(7−x)

24

​  

=14

⇒24(7−x)+24x=14x(7−x)⇒168=98x−14x  

2

⇒14x  

2

−98x+168=0

⇒x  

2

−7x+12=0⇒(x−3)(x−4)=0⇒x=3or4

Since A is faster than B, A's speed = 4 km/hr and B's speed = 3 km/hr