Ajit borrowed at Rs 22500 from bank and returned an amount of
Rs 22972.50 with an interest after 219 days find the S.I paid and
the rate of interest.
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1
Answer:
3.5%
Step-by-step explanation:
Here,
principle, P=₹22,500
Amount,A=₹22972.50
time,T=219/365
rate of interest,R=?
S.I.=A-P
S.I.= 22,972.50-22,500
S.I.=₹472.50
Now, we have to find rate of interest
so,
S.I.=(P×R×T)/100
472.50=(22,500×R×219)/(100×365)
R=(472.50×100×365)/(22500×219)
R=17246250/4927500
R=3.5%
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