Question

ajit carries a load of 17 kg from the ground to the height of 2m from the ground . calculate the work done by him





( answer is -333.2 J)​

Answer 1

Explanation:

m = 17 kg

h = 2 m

g = 9.8 m/s^2

Potential energy at the given height will be,

P.E. = mgh

P.E. = (17 kg) * (9.8 m/s^2) * (2 m)

P.E. = 333.2 kg*m/s^2 = 333.2 J

The work done by Ajit is 333.2 J

The work done by gravitational potential energy will be negative of the work done by Ajit i.e. -333.3 J

Answer 2

Answer:

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Explanation:

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