Question

Ajit got 10% less marks than Baljit and Kumar got 20% more than Baljit. If Kumar scored 960, how much did Ajit and Baljit score?



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Answer 1

Baljit's mark $x = 800$

Ajit's marks $= 720$

Explanation:  

Let Baljit got x marks  

Given that,

Ajit got marks $= x - \frac{10}{100}x$

Kumar got marks $= x + \frac{20}{100}x$

Kumar scored $960$  

On equating kumar's marks  

$x + \frac{20}{100}x$ $= 960$

$\frac{120}{100}x$ $= 960$

$x = \frac{960 \times 100}{120}$

Baljit's mark $x = 800$

Ajit's marks $= 800 - \frac{10}{100}\times 800$  

Ajit's marks $= 800 - 80 = 720$

Answer 2

Answer:

Let Baljit got x marks  

Given that,

Ajit got marks = x - \frac{10}{100}x=x−10010x

Kumar got marks = x + \frac{20}{100}x=x+10020x

Kumar scored 960960  

On equating kumar's marks  

x + \frac{20}{100}xx+10020x = 960=960

\frac{120}{100}x100120x = 960=960

x = \frac{960 \times 100}{120}x=120960×100

Baljit's mark x = 800x=800

Ajit's marks = 800 - \frac{10}{100}\times 800=800−10010×800  

Ajit's marks = 800 - 80 = 720=800−80=720