Ajit tendulkar has a certain average for 9 innings. in the tenth inning, he scores 100 runs thereby increasing his average by 8 runs. his new average is
Answers
In the 10th inning, he scored 100 runs then average became (x+8). And he scored (x+8)*10 runs in 10 innings.
Now,
=>9x+100 = 10*(x+8)
Or, 9x+100 = 10x+80
Or, x = 100-80
Or, x = 20
New average = (x+8) = 28 runs.
Given:
The average of Ajit increases by 8 runs in the tenth inning.
Ajit scored runs in 9 innings.
The runs scored in the tenth inning are 100.
To find:
New average of Ajit.
Solution:
The average of terms is the ratio of the sum of the terms and the total number of terms.
Average = sum of terms / total count of terms
Since Ajit scored a certain average for nine innings,
Therefore, let us assume the average of nine innings as X.
The total innings is 9.
Average for nine innings = Total score of Ajit / Total innings
The total score of Ajit = 9X
In the tenth inning,
Runs scored by Ajit = 100
Average increases by 8 in the tenth inning.
Therefore,
Average for ten innings = average of 9 innings + 8
= X + 8
Total runs scored by Ajit in ten innings = Total runs scored in nine innings + 100
Total count of innings = 10
Putting all the values in the formula for average,
X + 8 = (9X + 100)/ 10
10X + 80 = 9X + 100
10X -9X = 100 – 80
X = 20
Average for ten innings = X + 8
= 20 + 8
Average for ten innings = 28
The new average of Ajit after ten innings is 28.