Question

Ajit walked 5 km. East from A. After turning left he walked 3 km. Then he
turned in South-east direction and walked 5 km. Then he turned west
and walked 4 km. Finally he turned left and walked 12 km Then
How far Ajit is from his original place?
(A) 13 km
(C) 18 km
(B) 17 km
(D) 7 km​

Answer 1

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Ajit is 17 km away from its original position A

Answer 2

Answer:

(A) 13 km

Step-by-step explanation:

Given that ,

Ajit walked 5km east from point A.

He turn left and walked = 3km

again he turn in south-east direction and

walked = 5km

again he turn west and walked = 12 km

To find the distance between original point A to final point.

So,

from the figure we can conclude that walking from poin B coincide again at point B at E.

Therefore, the distance from original point to final point is distance between point A and F.

So, from the figure,

AF² = AB² + BF²

AF² = (5)² + (12)²

AF² = 25 + 144

AF² = 169

AF =√169

AF = 13 km

Therefore the correct option is (A) 13 km.

THANKS.

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