Question

Ajoba and Prav drive to work. Ajoba drives 45 miles in 2.5 hours. Prav drives 74 km in 1 hour 15 min. Work out the difference between their average speeds in km/h. 1 mile = 1.6 km

Answer 1

Answer:

66 km/hour

Step-by-step explanation:

We have,

Ajoba and Prav drive to work. Ajoba drives 45 miles in 2.5 hours. Prav drives 74 km in 1 hour 15 min.

1 mile = 1.6 km

45 miles = 72.42 km

74 miles = 119.0 km

1 hour 15 min means 1.25 hours

Average speed of Ajoba is :

v_1=\dfrac{72.42 }{2.5}=28.96\ km/hv

1

=

2.5

72.42

=28.96 km/h

Average speed of Prav,

v_2=\dfrac{119}{1.25}=95.2\ km/hv

2

=

1.25

119

=95.2 km/h

Difference in average speed of Ajoba and Prav is :

\begin{gathered}v=v_2-v_1\\\\v=v_2-v_1\\\\v=95.2-28.96\\\\v=66.24\ km/h\end{gathered}

v=v

2

−v

1

v=v

2

−v

1

v=95.2−28.96

v=66.24 km/h

So, the difference in average speed of Ajoba and Prav is 66.24 km/h.