Question

AK40°
30°C
1. (i) In Figure (1), O is the centre of the circle. If
OAB = 40° and LOCB = 30°, find AOC.
(ii) In Figure (2), A, B and Care
three points on the circle with
centre O such that ZAOB = 90°
90° KO.
and AOC = 110°. Find BAC.​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

A0C =360-(40+30)=270

BAC =360-(110+90)=160