Question

aka initially at rest pics of a velocity of 72 km per hour in 20 seconds if the mass of car is 1000 kilogram find the force developed by its engine distance covered by the car

Answer 1

u = 0 m/s

v = 72 km/h = 72 *5/18 m/s

= 20 m/s

t = 20 s

As v = u + a t

so, 20 = 0 + a * 20

so, a = 20/20 = 1 m/s^2

Now mass = 1000 kg

a = 1 m/s^2 and

Force, F = ma

so, F = 1000 * 1 = 1000 kg m/s^2

= 1 kN