× अक्ष से बिंदु p(2,3) की दूरी है
Answers
Given : बिंदु p(2,3)
Point p ( 2 ,3 )
To find : x अक्ष से बिंदु p(2,3) की दूरी
distance of point p(2,3) from x axis
Solution:
x axis equation is y = 0
0.x + 1.y + 0 = 0
perpendicular Distance of point (x₁ , y₁) from line ax + by + c = 0 is given by
| (a(x₁) + by₁ + c)/√a² + b² |
Hence distance of p(2,3) from x axis 0.x + 1.y + 0 = 0
= | (0(2) + 1(3) + 0)/√0² + 1² |
= 3
Hence distance of point p(2,3) from x axis is 3 units
x अक्ष से बिंदु p(2,3) की दूरी 3 है
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SOLUTION
TO DETERMINE
The distance of the point P(2,3) from X axis
EVALUATION
First Method :
Here the given point is P(2,3)
Now
Abscissa = 2 which is positive
Ordinate = 3 which is negative
So the point lies on 1st quadrant
Abscissa = 2
⇒ Distance from Y axis = 2 unit
Ordinate = 3
⇒ Distance from X axis = 3 unit
Second Method :
We draw a perpendicular from P on X axis
It cuts X axis at A(2,0)
Hence the required distance from X axis
= 3 - 0 unit ( Since Abscissa are same )
= 3 unit
Figure : Figure is referred to the attachment
FINAL ANSWER
The distance of the point P(2,3) from X axis
= 3 unit
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