Akash starting from rest acquire a velocity of 20 m per second in 6 second if the mass of the car is 1200 kilogram calculator force
HarithaMuliki2227:
hai
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thus the ans is 4000 N.
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Given,
Initial velocity ( u ) = 0
Final velocity ( v ) = 20 m/s
Time ( t ) = 6 seconds
Mass = 1,200 kg
Force = ?
We know that,
⇒ Force = Mass × Acceleration
We have already Mass , so we need to find acceleration.
We can find acceleration of a body if one group among these is given :
1. Time , Initial Velocity and Final Velocity.
2. Displacement , Initial velocity and Time.
3. Displacement , Initial velocity and Final velocity.
Fortunately, we have one group among these.
Then , why are we waiting ? Let's do it !
Using formula,
⇒ Acceleration = ( Final velocity - Initial velocity ) Time taken
⇒ a = ( v - u ) / t
⇒ a = [ ( 20 m/s ) - 0 ] / 6 s
⇒ a = ( 20 m/s ) / 6 s
•°• a = ( 20/6 ) m/s²
Now,
⇒ Force = Mass × Acceleration
⇒ Force = ( 1,200 kg ) × ( 20/6 ) m/s²
⇒ Force = ( 200 × 20 ) kg m/s²
⇒ Force = 4,000 kg m/s²
•°• Force = 4,000 N
Initial velocity ( u ) = 0
Final velocity ( v ) = 20 m/s
Time ( t ) = 6 seconds
Mass = 1,200 kg
Force = ?
We know that,
⇒ Force = Mass × Acceleration
We have already Mass , so we need to find acceleration.
We can find acceleration of a body if one group among these is given :
1. Time , Initial Velocity and Final Velocity.
2. Displacement , Initial velocity and Time.
3. Displacement , Initial velocity and Final velocity.
Fortunately, we have one group among these.
Then , why are we waiting ? Let's do it !
Using formula,
⇒ Acceleration = ( Final velocity - Initial velocity ) Time taken
⇒ a = ( v - u ) / t
⇒ a = [ ( 20 m/s ) - 0 ] / 6 s
⇒ a = ( 20 m/s ) / 6 s
•°• a = ( 20/6 ) m/s²
Now,
⇒ Force = Mass × Acceleration
⇒ Force = ( 1,200 kg ) × ( 20/6 ) m/s²
⇒ Force = ( 200 × 20 ) kg m/s²
⇒ Force = 4,000 kg m/s²
•°• Force = 4,000 N
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