Question

Akash when going slower by 15Km/hr reaches late by 45hours.If he goes faster by 10 km/hr from his original speed, he reaches early by 20 hours than original time.Find the distance he covers?​

Answer 1

Answer:

9750 km/hr

Step-by-step explanation:

Let u be the original spped of Akash

45 u = 15 ( t + 45) ---------- 1

20 u = 10 ( t - 20) ---------- 2

from eqn. 1 & 2

2 t + 90 = 3t - 60

t = 150 hours. and u = 65 km / h

Distance covered = ut = 9750 km

Hope it helps!!!!!! :)