Question

Akbar, Ali and Arman are 3 brothers. The ratio of Akbar's age to Arman's age is 1 : 2
and the ratio of Akbar's age to Ali's age is 2 : 5. If the eldest boy is 10 years old, how
old is the youngest one?

Answer 1

Answer:

Akbar / Arman = 1 / 2

Akbar / Ali = 2 / 5

 

Ali is the oldest = 10 years

 

Akbar =2 * Ali / 5 =2 * 10 / 5 = 4 years old

 

4 / Arman = 1 / 2

Arman =2 * 4 = 8 years old

 

Check: Akbar / Arman =4 / 8 =1 : 2

Akbar / Ali = 4 / 10 = 2 / 5 =2 : 5

Step-by-step explanation:

BRAINLEST PLZ

Answer 2

Answer:

The youngest boy Akbar is 4 years old.

Step-by-step explanation:

• Let Arman  be x years old.

• The  boy Akbar is y years old .

• Let Ali be z years old.

• The ratio of Akbar's age to Ali's age is 2 : 5.

So, we can write y : z = 2 : 5

                          ⇒ $\frac{y}{z}$   =  $\frac{2}{5}$

                          ⇒ 5y  = 2z

                          ⇒ y    = $\frac{2}{5}$ z ...................................................................(i)

Hence y < z .........................................(ii)

So, we can say Akbar is younger than Ali

• Again, the ratio of Akbar's age to Arman's age is 1 : 2.

so, y : x = 1 : 2

⇒    $\frac{y}{x}$    =  $\frac{1}{2}$

⇒    x = 2y

⇒    y = x/2 .......................................................................................(iii)

Hence y < x ................................................................................(iv)

From (i) and (iii), we can write

 $\frac{2}{5}$ z = $\frac{x}{2}$

or, x =   $\frac{4}{5}$ z ........................................................................................(v)

so, z > x..............................................(vi)

Now, from (ii),(iv) and(vi) , we can say

z>x>y

So, Ali is the eldest boy whose age is 10 years.

Akbar is the youngest boy.

Akbar's age  y =  $\frac{2}{5}$ z =  $\frac{2}{5}$ of 10 = 4 years.

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