Math, asked by bish97, 10 months ago

Akbar, Birbal, Chaitanya, David & Ehasaan play a game of coins. Akbar says to Birbal, "If you give me 30 coins, you will have as many as Ehsaan has and if I give you 30 coins, you will have as many as David has." Akbar and Birbal together have 100 coins more than what David and Ehsan together have. If Birbal has 20 coins more than what Chaitanya has and the total number of coins that they have is 1330, how many coins does Birbal have?
A. 220B. 230C. 250D. 350​

Answers

Answered by ItzLava90
3

Answer:

Option: C

Option: CExplanation:

Clearly, we have :

Birbal-30 = Ehsaan ...(i)

Birbal + 30 = David ...(ii)

Akbar+Birbal = David+Ehsaan+100 ...(iii)

Birbal = Chaitanya + 20 ...(iv)

Akbar+Birbal+Chaitanya+David+Ehsaan= 1330 ...(v)

From (i) and (ii), we have : 2 Birbal=D+E ...(vi)

From (iii) and (vi), we have : Akbar=Birbal + 100 ...(vii)

Using (iv), (vi) and (vii) in (v),

we get:

(Birbal + 100) + Birbal + (Birbal - 20) + 2(Birbal) = 1330

5(Birbal) = 1250

Birbal = 250

Answered by ripusingh0189
0

\matchcal{\red{Option: C}}

Explanation;

Clearly, we have :

Birbal-30 = Ehsaan ...(i)

Birbal + 30 = David ...(ii)

Akbar+Birbal = David+Ehsaan+100 ...(iii)

Birbal = Chaitanya + 20 ...(iv)

Akbar+Birbal+Chaitanya+David+Ehsaan= 1330 ...(v)

From (i) and (ii), we have : 2 Birbal=D+E ...(vi)

From (iii) and (vi), we have : Akbar=Birbal + 100 ...(vii)

Using (iv), (vi) and (vii) in (v), we get:

(Birbal + 100) + Birbal + (Birbal - 20) + 2(Birbal) = 1330

5(Birbal) = 1250

Birbal = 250

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