Math, asked by anas5252, 8 months ago

Akhil is twice as old as Bharath. Ten years ago, Akhil's age was four times Bharath's age. Find Akhil's present age.
20 years​

Answers

Answered by Anonymous
66

Given

Akhil is twice as old as Bharath. Ten years ago, Akhil's age was four times Bharath's age.

Find out

Find the present age of Akhil

Solution

Let the present age of Bharath be x then Akhil age be 2x

  • After 10 years ago
  • Bharath's age = (x - 10)
  • Akhil's age = (2x - 10)

**According to the given condition**

2x - 10 = 4(x - 10)

→ 2x - 10 = 4x - 40

→ 40 - 10 = 4x - 2x

→ 2x = 30

→ x = 30/2 = 15

Hence,

  • Present age of Bharath = x = 15years
  • Present age of Akhil = 2x = 2*15 = 30years
Answered by Ataraxia
6

Let the age of Bharath = x

And age of Akhil = 2x

10 years ago ,

Age of Bharath = x-10

Age of Akhil = 2x-10

» 2x-10 = 4(x-10)

» 2x-10 = 4x-40

» 4x-2x = 40-10

» 2x = 30

» x = 15

PRESENT AGE OF BHARATH = 15

PRESENT AGE OF AKHIL = 30

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