Math, asked by aathi2007, 1 month ago

akila scored 80percentage of marks in a examination if her score was 576 marks. then find the maximum marks of the examination​

Answers

Answered by pratimaguptapkg
0

Answer:

totalscorehegained=576

we \: need \: to \: < /p > < p > find \: 80\% \: of \: total \: < /p > < p > < /p > < p > marks\:he\: gained \: i.e \: 576weneedto</p><p>find80%oftotal</p><p></p><p>markshegainedi.e576

let total score = x

{80\%\:of\:x\:=576}80%ofx=576

80 = \frac{576}{x} \times 10080=x576×100

80= \frac{57600}{x}80=x57600

x= \frac{80}{57600}x=5760080

x=720x=720

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Answered by MasterDhruva
6

Given :-

Percent scored by Akila :- 80%

Marks obtained by Akila :- 576

\:

To Find :-

The total marks of the examination.

\:

How to do :-

Here, we are given with the marks obtained by a girl in her exam and she gad scored 80% in her examination. So, this percentage represents the marks obtained by her in percent form. So, the percentage and the value of that percentage is given to us. We are asked to find the maximum marks of this examination. So, we'll take the maximum marks of this examination as a variable and then find the value of that. Then, we can verify the answer by using the formula of calculating percentage. So, let's solve!!

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Solution :-

{\sf \leadsto \dfrac{Obtained \: marks}{Total \: marks} \times 100}

Substitute the given values.

{\tt \leadsto \dfrac{576}{x} \times 100 = 80}

Multiply 576 with 100.

{\tt \leadsto x = \dfrac{576 \times 100}{x} = 80}

Multiply the numerator values.

{\tt \leadsto x = \dfrac{57600}{x} = 80}

Shift the value x from LHS to RHS, changing it's sign

{\tt \leadsto 57600 = 80 \times x}

Shift the value 80 from RHS to LHS, changing it's sign.

{\tt \leadsto x = \dfrac{57600}{80} = \pink{\underline{\boxed{\tt 720 \: \: marks}}}}

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Verification :-

{\tt \leadsto 80 \bf\% \tt \: \: of \: \: 720 = 576}

{\tt \leadsto \dfrac{80}{100} \times 720 = 576}

{\tt \leadsto \dfrac{4}{5} \times 720 = 576}

{\tt \leadsto \dfrac{4 \times 720}{5} = 576}

{\tt \leadsto \dfrac{2880}{5} = 576}

{\tt \leadsto 576 = 576}

{\sf \leadsto LHS = RHS}

\:

Hence solved !!

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