Math, asked by rakshithabs10, 9 months ago

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Answered by banuarun333k
1

Answer:

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Step-by-step explanation:

given

first term(a) = 2

last term = 50

Sum = 442

now 50 = 2+(n-1)d

48 = nd-d

d = nd-48

now sum = 442

n/2(a+l) = 442

n/2(2+50)=442

n/2 (52) =442

n x 26 = 442

n = 442/26

n = 17

now from(1)

48 = (n-1)d

d = 48/(n-1)

d = 48 /16

d = 3

Hence the common difference is 3

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