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Step-by-step explanation:
given
first term(a) = 2
last term = 50
Sum = 442
now 50 = 2+(n-1)d
48 = nd-d
d = nd-48
now sum = 442
n/2(a+l) = 442
n/2(2+50)=442
n/2 (52) =442
n x 26 = 442
n = 442/26
n = 17
now from(1)
48 = (n-1)d
d = 48/(n-1)
d = 48 /16
d = 3
Hence the common difference is 3
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