Question

Akon and a cylinder have equal bases the height of the cone is half the height of the cylinder what is the ratio of their volumes​

Answer 1

Answer:

Ratio - 6:1

Step-by-step explanation:

Let the height of cylinder be 'h'

So, the height of cone = $\frac{1}{2}h$= H

Radius of cone = Radius of cylinder = r

Ratio of their volumes = $\frac{\pi r^{2} h }{\frac{1}{3} \pi r^{2} H}$

                               = $\frac{\pi r^{2} h }{\frac{1}{3} \pi r^{2} \frac{1}{2}h}$

Cancelling $\pi$, h and r, we get

                              =$\frac{1}{\frac{1}{3}.\frac{1}{2} }$

                              = $\frac{1}{\frac{1}{6} }$

                              = $\frac{6}{1}$

                              =6:1

Answer 2

Step-by-step explanation:

Let, radius of cone & cylinder is 'y'.height of cylinder is '2z'. the height of cone is half of height of cylinder so it's height is 'z'. volume of cone is = π×r×r×h÷3 volume of cylinder is= π×r×r×h ratio of volume of cone and cylinder is= π×r×r×h÷3:π×r×r×h so, r=y, height of cone= z, height of cylinder =2z therefore π×y×y×z÷3:π×y×y×2z =1:6 The raito of volume of cone and cylinder is 1:6