Math, asked by vhihf8, 1 month ago

Akram is twice as old as Shaziya. Five years ago his age was three times Shaziya's age. Find their present ages.​

Answers

Answered by Anonymous
24

Answer:

Given :-

  • Akram is twice as old as Shariya.
  • Five years ago his age was three times Shaziya's age.

To Find :-

  • What is their present ages.

Solution :-

Let,

\mapsto \bf Present\: Age_{(Shaziya)} =\: a\: years

\mapsto \bf Present\: Age_{(Akram)} =\: 2a\: years

5 years ago their ages will be :

\leadsto \sf Age_{(Shaziya)} =\: (a - 5)\: years

\leadsto \sf Age_{(Akram)} =\: (2a - 5)\: years

According to the question,

\bigstar Five years ago his age was three times Shaziya's age.

\small\leadsto \bf \bigg\{Age_{(Akram)}\bigg\} =\: 3\bigg\{Age_{(Shaziya)}\bigg\}

\implies \sf 2a - 5 =\: 3(a - 5)

\implies \sf 2a - 5 =\: 3a - 15

\implies \sf 2a - 3a =\: - 15 + 5

\implies \sf {\cancel{-}} a =\: {\cancel{-}} 10

\implies \sf\bold{\purple{a =\: 10}}

Hence, their required present ages are :

Present Age Of Shaziya :

\longrightarrow \sf Present\: Age_{(Shaziya)} =\: a\: years

\longrightarrow \sf\bold{\red{Present\: Age_{(Shaziya)} =\: 10\: years}}

Present Age Of Akram :

\longrightarrow \sf Present\: Age_{(Akram)} =\: 2a\: years

\longrightarrow \sf Present\: Age_{(Akram)} =\: (2 \times 10)\: years

\longrightarrow \sf\bold{\red{Present\: Age_{(Akram)} =\: 20\: years}}

{\footnotesize{\bold{\underline{\therefore\: The\: present\: age\: Shaziya\: and\: Akram\: is\: 10\: years\: and\: 20\: years\: respectively\: .}}}}

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VERIFICATION

\leadsto \sf 2a - 5 =\: 3(a - 5)

By putting a = 10 we get,

\leadsto \sf 2(10) - 5 =\: 3(10 - 5)

\leadsto \sf 20 - 5 =\: 3(5)

\leadsto \sf\bold{\green{15 =\: 15}}

Hence, Verified.

Answered by Anonymous
46

Answer:

Given :-

  • Akram is twice as old as Shaziya. Five years ago his age was three times Shaziya's age.

To find :-

  • Find their present ages.

Explanation :-

  • Present age of Shaziya =x years
  • Present age of Akram =2x years.

♧5 years ago:-

  • Ages becomes,
  • Age of Shaziya =x-5 years
  • Age of Akram=2x-5 years.

♧It is 3 times more than Shaziya age,

  • Age of Akram=3(Age of Shaziya)
  • Now applying the values ,
  • 2x - 5 = 3x - 15
  • 2x - 3x =  - 15 + 5
  •  - x =  - 10
  • x = 10

♧Therefore ,

  • Required ages is ,
  • Age of Shaziya =x=10 years
  • Age of Akram= 2x=2×10=20 years.

♧Hope it helps u mate .

♧Thank you .

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