Akram is twice as old as Shaziya. Five years ago his age was three times Shaziya's age. Find their present ages.
Answers
Answered by
24
Answer:
Given :-
- Akram is twice as old as Shariya.
- Five years ago his age was three times Shaziya's age.
To Find :-
- What is their present ages.
Solution :-
Let,
❒ 5 years ago their ages will be :
According to the question,
Five years ago his age was three times Shaziya's age.
Hence, their required present ages are :
❒ Present Age Of Shaziya :
❒ Present Age Of Akram :
▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃
★ VERIFICATION ★
By putting a = 10 we get,
Hence, Verified.
Answered by
46
Answer:
Given :-
- Akram is twice as old as Shaziya. Five years ago his age was three times Shaziya's age.
♧To find :-
- Find their present ages.
□Explanation :-
- Present age of Shaziya =x years
- Present age of Akram =2x years.
♧5 years ago:-
- Ages becomes,
- Age of Shaziya =x-5 years
- Age of Akram=2x-5 years.
♧It is 3 times more than Shaziya age,
- Age of Akram=3(Age of Shaziya)
- Now applying the values ,
♧Therefore ,
- Required ages is ,
- Age of Shaziya =x=10 years
- Age of Akram= 2x=2×10=20 years.
♧Hope it helps u mate .
♧Thank you .
Similar questions