Math, asked by erajpoot777, 9 months ago

Akram thought of a number, added 7
multiplied by 3, took away 5 and divided by 4
to give an answer of 7. What was the starting
number?​

Answers

Answered by frenchfries20
5

Answer:

4

Step-by-step explanation:

LET THE NUMBER BE x

ACCORDING TO THE QUESTION:

(x+7)3-5/4 = 7

3x+21 -5/4= 7

3x+21-5= 7×4

3x+16=28

3x=28-16

3x=12

x=12/3

x=4

hope it helps!

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Answered by LeParfait
2

Solution:

Let the number be x.

  • Added 7 = x + 7

  • Multiplied by 3 = 3 (x + 7) = 3x + 21

  • Took away 5 = 3x + 21 - 5 = 3x + 16

  • Divided by 4 = (3x + 16)/4

Given, resulting number = 7

or, (3x + 16)/4 = 7

or, 3x + 16 = 28

or, 3x = 12

or, x = 4

Answer: required number is 4.

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