Akshay, Bimal and Chirag work on a construction project. All of them work with equal efficiency and
can together complete the project in 20 days. If only 2 of them work on it at a time and all of them
spend equal days to complete the project, how many days would each one of them work for, to
complete the work?
Answers
Given :- Akshay, Bimal and Chirag work on a construction project. All of them work with equal efficiency and can together complete the project in 20 days. If only 2 of them work on it at a time and all of them spend equal days to complete the project, how many days would each one of them work for, to complete the work ?
Solution :-
given that, efficiency of all of them is same.
So,
Let us assume that, they all do x unit of work daily .
now, given that, all together complete the project in 20 days.
Than,
→ 1/x + 1/x+ 1/x = 1/20
→ 3/x = 1/20
→ x = 60 units .
Now, it has been said only 2 of them work on it at a time to complete the project .
Therefore,
→ Total days take by 2 of them at a time = (1/60+ 1/60) = 1/30 = 30 days.
we can say that, It will take total 30 days to complete the project when they work two at a time . { Like AB, BC, CA } .
Hence, we can say that, they took (10 + 10) days each to complete the project.
∴ each worked for 20 days.
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