(Al = 27u , Fe = 56u , O =16u are atomic mases) How much of iron we get if 54Kg of Aluminum is used?
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saivivek16:
Answer will 112 kgs
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3
according to balanced equation
54UAl + 160UFe2O3 + 102UAl2O3+112U g
hence 54g------112gAl
so 54kg ---- 112gFe
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3
hope u got ur answer
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