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Answered by
6
Answer:
QUADRATIC EQUATION:
Suppose,
3x²+2x+3=0. is a Quadratic equation.
If we compare it with ax²+bx+c=0
then we get,
a=3, b=2 and c=3
Here, We can find,
Alpha +Beeta=-b/a=-2/3
Answered by
1
Answer:
p(x) = ax² + bx + c
∴ α + β = -(coefficient of x) /coefficient of x² = -b/a
αβ = constant /coefficient of x² = c/a
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