Question

Al+ Fe2 O3 gives rise to Al2 O3 +fe.
(atomic masses of Al = 274, Fe=sburg
0- 160)
Calculate the amount of aluminium
required to get 1120kg of iroo by the
above reaction​

Answer 1

in the following reaction the nfactor for aluminum is 3 as Al---Al+3e- is 3 as three electrons are exchanged

similarly the n Factor for copper is 2

weight×nfactor/molwt=Q/F

we know that Q and F is constant for Al as well as Cu hence we can write the as

Wal/mol.wt al×n1 =Wcu/ mol wtcu×n2

1120×3/27=Wcu×2/63.5

Wcu=1120×63.5/9×2

Wcu=3951g

I hope this helps ( ╹▽╹ )

Answer 2

GD MRNG DEAR

HAVE A GREAT DAY AHEAD