Al+fe203----->Al203+fe calculate the amount of aluminium required to get 1120kg of iron by the above equation
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Answer:
Let's consider the equation first.
F
e
2
O
3
+
2
A
l
=
A
l
2
O
3
+
2
F
e
It says that 2 moles of aluminium will react with 1 mole of Iron (III) Oxide to form 1 mole of Aluminium Oxide and 2 moles of Iron.
So, Unitary method.
54
g Al will react with
→
160
g of
F
e
2
O
3
1
g Al will react with
→
160
54
g of
F
e
2
O
3
52.6
g Al will react with
→
160
⋅
52.6
54
g of
F
e
2
O
3
≈
155.85
g of
F
e
2
O
3
Explanation:
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