Question

al Find the ratio in which x-axis divides the line segment joining
the points (3, 3) and (6, -6).​

Answer 1

Answer:

Ratio = 2:7

Step-by-step explanation:

Kindly refer the attachment

Answer 2

Answer:

$hello \: dear........$

X-axis divides the line segment joining the points (3,3) & (6,-6).

Let, the ratio be m:n

$formula \\ x \: coordinate = \frac{mx2 + nx1}{m + n} \\ y \: coordinate \: = \: \frac{my2 + ny1}{m + n}$

$0\: = \frac{6m + 3n}{m + n} \\ m + n = 6m + 3n \\ 6m - m = n - 3n \\ 5m = - 2n \\ \frac{m}{n} = \frac{ - 2}{5}$

❣FOLLOW ME GUYZ❣