Question

Al + HCl → AlCl3 + H2

Answer 1

Explanation:

Al2+2HCl--2AlCl3+H2

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Answer 2

Answer:

2Al (s) + 6HCl (l) ⟶ 2AlCl₃ (s) + 3H₂ (g)

Explanation:

Al + HCl ⟶ AlCl3 + H₂

In this reaction, aluminium ( Al ) reacts with hydrochloric acid ( HCl ) to form aluminum chloride ( AlCl₃ ) and hydrogen gas ( H₂ ).

Atoms in reactants side:

• Al = 1
• H = 1
• Cl = 1

Atoms in products side:

• Al = 1
• Cl = 3
• H = 2

By law of conservation of mass, we know that the number of atoms of each element in reactants side must be equal to number of atoms in products side.

To balance chlorine atom in product side, we multiply AlCl₃ by 2.

Al + HCl ⟶ 2AlCl₃ + H₂

Atoms in reactants side:

• Al = 1
• H = 1
• Cl = 1

Atoms in products side:

• Al = 2
• Cl = 6
• H = 2

To balance chlorine atom in reactant side, we multiply HCl by 6.

Al + 6HCl ⟶ 2AlCl₃ + H₂

Atoms in reactants side:

• Al = 1
• H = 6
• Cl = 6

Atoms in products side:

• Al = 2
• Cl = 6
• H = 2

To balance hydrogen atom in product side, we multiply H₂ by 3.

Al + 6HCl ⟶ 2AlCl₃ + 3H₂

Atoms in reactants side:

• Al = 1
• H = 6
• Cl = 6

Atoms in products side:

• Al = 2
• Cl = 6
• H = 6

Now, in reactant side, 1 aluminium atom is missing. So, we multiply Al by 2 to balance both sides.

2Al (s) + 6HCl (l) ⟶ 2AlCl₃ (s) + 3H₂ (g)

This is the balanced chemical equation.