Question

AL(OH)³–AL²O³+H²O balance ​

Answer 1

Step-by-step explanation:

Molecular weight of given compound is and basicity is

$78$

. Therefore, equivalent weight is

$\frac{78}{3} = 26$

Answer 2

Answer:

Answer:

Here is the chemical equation.

Al2(SO4)3+NaOH=Al(OH)3+Na2SO4

First of all equal the no. of atoms on both side of the equation.

Reactants            =         Products  

Al            2           =              Al            1 X 2 = 2

SO4        3           =             SO4          1 X 3 =3  

Na      1 X 6 = 6   =              Na           2 X 3 =6

OH      1 X 6=6    =              OH           2 X 3 = 6  

Balanced equation:

Al2(SO4)3 + 6NaOH ------------->2Al(OH)3 + 3Na2SO4

Step-by-step explanation: