Question

AL
So
30) The diameter of the base of a cylinder is 21cm and its height is 18cm. A
hemisphere and a cone of diamter same as that of cylinder are joined on
either sides of cylinder. If the height of cone is 9cm find the volume of solid so
obtained
​

Answer 1

Volume of the solid structure is 9702 cm³

Step-by-step explanation:

Diameter of the base of a cylinder = 21 cm

Height of the cylinder = 18 cm

Volume of the cylinder = $\pi r^{2}h$

V = $\pi (\frac{21}{2})^{2}\times 18$

V = 6237 cm³

Volume of the hemisphere with radius = 10.5 cm

Volume = $\frac{2}{3}\pi r^{3}=\frac{2}{3}\times (\frac{22}{7})\times (10.5)^{3}$

             = 2425.5 cm³

Volume of the cone of height 9 cm and radius 10.5 cm

Volume = $\frac{1}{3}\pi r^{2}h$

Volume of the cone = $\frac{1}{3}\times (\frac{22}{7})\times (10.5)^{2}\times 9=1039.5$ cm³

Now volume of the solid obtained = Volume of the cylinder + Volume of a cone + Volume of the hemisphere

= 6237 + 2425.5 + 1039.5

= 9702 cm³

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