Question

al The Curved surface area of a right
circular Cylinder of height 14 Cm is 88cm
find the diameter of the base of the
cylinder

​

Answer 1

Given :

• Height of the right circular cylinder , h = 14 cm
• Curved surface area of a right circular cylinder = 88 cm²

To Find :

The diameter of the base of the cylinder.

Solution :

We have ,

H = 14 cm

A = 88 cm²

r = ?

We know that :

Curved surface of the right circular cylinder

$\sf=2\pi\:r\:h$

Put the given values

$\sf\:88=2\times\dfrac{22}{7}\times\:r\times14$

$\sf\:88=2\times22\times\:2\times\:r$

$\sf\:r=\dfrac{88}{88}$

$\sf\:r=1cm$

Now ,

Diameter of the base of the culino

= 2× Radius of the cylinder

= 2× 1 = 2 cm

Therefore, The diameter of the base of the cylinder is 2 cm .

Answer 2

Answer:

Given :

Height of the right circular cylinder , h = 14 cm

Curved surface area of a right circular cylinder = 88 cm²

To Find :

The diameter of the base of the cylinder.

Solution :

We have ,

H = 14 cm

A = 88 cm²

r = ?

We know that :

Curved surface of the right circular cylinder

\sf=2\pi\:r\:h=2πrh

Put the given values

\sf\:88=2\times\dfrac{22}{7}\times\:r\times1488=2×

7

22

×r×14

\sf\:88=2\times22\times\:2\times\:r88=2×22×2×r

\sf\:r=\dfrac{88}{88}r=

88

88

\sf\:r=1cmr=1cm

Now ,

Diameter of the base of the culino

= 2× Radius of the cylinder

= 2× 1 = 2 cm

Therefore, The diameter of the base of the cylinder is 2 cm .