Question

al The radius of 197 Ag is the radius of the. 197 Ag is 6.2 fm. Determine the radius of 4 He.​

Answer 1

Answer:

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Answer 2

Given: The radius of Ag(mass number= 197) is 6.2 fm.

To find: Radius of He (mass number=4)

Explanation: The radius of a nucleus is directly proportional to the cube root of the mass number of the nucleus.

Therefore, the formula of the radius is given by:

$r = r1 \: ({a})^{ \frac{1}{3} }$

where r1 is a constant and a is the mass number of the nucleus.

Using formula for Ag(mass number= 197):

$= > 6.2= r1 \times ( {197)}^{ \frac{1}{3} }$

$= > 6.2 = r1 \times 5.81$

=>r1 = 6.2/5.8

=> r1 = 1.07 fm

For He( mass number= 4):

$= > r = 1.07 \times ( {4})^{ \frac{1}{3} }$

$= > r = 1.07 \times 1.59$

=> r = 1.7 fm

Therefore, the radius of He( mass number= 4) is 1.7 fm.