alcohol
alcohol →H-C=C-H
X +2KOH
here X'is
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R−Cl+KOH(aq)→R−OH+KCl
R−CH
2
−CH
2
−Cl+KOH(alc)→R−CH=CH
2
+KCl+H
2
O
The ionization of aqueous KOH produces hydroxide ions which are strong nucleophiles. Hence, alkyl chlorides undergo substitution to form alcohol.
Alcoholic KOH solution gives alkoxide ion which is a strong base.
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