Question

alculate the electron concentration of charge carriers at 300 K given

that The intrinsic carrier density is 1.5 × 1016 m–3 and hole

concentration is 2 × 1022 m
​

Answer 1

We have to calculate the electron concentration of charge carries at 300K given that intrinsic carrier density is 1.5 × 10¹⁶ m¯³ and hole concentration is 2 × 10²² m¯³.

solution : using formula, $n_e\times n_h=n_i^2$

where $n_e$ is the electron concentration of charge carriers.

$n_h$ is the hole concentration

and $n_i$ is the intrinsic carrier density.

here, $n_i$ = 1.5 × 10¹⁶ m¯³

$n_h$ = 2 × 10²² m¯³

so, $n_e=\frac{n_i^2}{n_h}$

= (1.5 × 10¹⁶)²/(2 × 10²²)

= 2.25 × 10¹⁰/2

= 1.125 × 10¹⁰ m¯³

Therefore the electron concentration of charge carriers at 300 K is 1.125 × 10¹⁰ m¯³.

also read similar questions : In an intrinsic semiconductor tue density of conduction electron is 7.07×10 to power 15 m—³ is doped with indium the den...

https://brainly.in/question/14557224

For a p-type semiconductor, which of the followmg statements is true ?

I. Electrons are the majority carriers and triva...

https://brainly.in/question/15264611