Math, asked by subhashattri07, 6 days ago

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Answered by mss0144
1

ʜᴇʀᴇ ɪs ʏᴏᴜʀ ᴀɴsᴡᴇʀ ᴘʟᴇᴀsᴇ ᴍᴀʀᴋ ᴀs ʙʀᴀɪɴʟɪᴇsᴛ

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Answered by sandy1816
6

\huge\underline\bold\red{★Answer★}

let \:  \:  \:  y = {cot}^{ - 1} ( \frac{ - 1}{ \sqrt{3} } ) \\  \implies coty =  \frac{ - 1}{ \sqrt{3} }   \\  \implies coty  =  - cot( \frac{\pi}{3} ) \\  \implies coty = cot(\pi -  \frac{\pi}{3}  ) \\  \implies coty = cot \frac{2\pi}{3}  \\  \implies  y  =  \frac{2\pi}{3}  \\ since \:  \: the \:  \: principal  \: \: brunch \:  \: of \: cot ^{ - 1} is \:  \: (0 \:  \: \pi) \\ hence \:  \: pricipal \: value \: is \:  \frac{2\pi}{3}

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