Question

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chemistry

Answer 1

Formula of Gibbs free energy of mixture is given by 



Where x₁ is the mole fraction of benzene ,
x₂ is the mole fraction of toluene , 

n is the total number of moles 

R is the universal gas constant e.g., R = 25/3 J/Kmol

T is the temperature .

Now, x₁ = (n₁)/(n₁ + n₂) = 6/(6 + 2.5) = 6/8.5 = 12/17 
x₂ = n₂/(n₁ + n₂) = 2.5/(6 + 2.5) = 5/17 

Now, 

n = n₁ + n₂ = 6 + 2.5 = 8.5 

R = 25/3 J/Kmol

T = 298K 



=12.5 × 298/3 [12ln(12/17) + 5ln(5/17) ] J 

= 12.5 × 298/3 × (-10.2985) 

= -12.787 kJ

Answer 2

Answer :-

________________________

Formula of Gibbs free energy of mixture is given by 

∆mixG = nRT ( x1 in x1 + x2 in x2 )

Where x₁ is the mole fraction of benzene ,
x₂ is the mole fraction of toluene ,
n is the total number of moles
R is the universal gas constant e.g., R = 25/3 J/Kmol
T is the temperature .

Now , x₁ = (n₁)/(n₁ + n₂) = 6/(6 + 2.5) = 6/8.5 = 12/17
x₂ = n₂/(n₁ + n₂) = 2.5/(6 + 2.5) = 5/17

And now ,

∆mixG = nRT ( x1 in x1 + x2 in x2 )

n = n₁ + n₂ = 6 + 2.5 = 8.5 
R = 25/3 J/Kmol
T = 298K 

∆ Gmix = 8.5 × 25/3 × 298 [12/17ln(12/17) + 5/17ln(5/17)]
=12.5 × 298/3 [12ln(12/17) + 5ln(5/17) ] J 
= 12.5 × 298/3 × (-10.2985) = -12.787 kJ

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