Question

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chemistry

Answer 1

A.∂G=nRT(x1lnx1 + x2lnx2)

Given:-

n=6+2.5= 8.5

R=8.314

T=298K

x1=6/8.5 & x2=2.5/8.5

     =0.7058.    =0.2941

∂G= 8.5×8.314×298×2.303(0.7058log0.7058+ 0.2941log0.2941

∂G= 12757.9 J

Answer 2

Answer :-

________________________

Formula of Gibbs free energy of mixture is given by 

∆mixG = nRT ( x1 in x1 + x2 in x2 )

Where x₁ is the mole fraction of benzene ,
x₂ is the mole fraction of toluene ,
n is the total number of moles
R is the universal gas constant e.g., R = 25/3 J/Kmol
T is the temperature .

Now , x₁ = (n₁)/(n₁ + n₂) = 6/(6 + 2.5) = 6/8.5 = 12/17
x₂ = n₂/(n₁ + n₂) = 2.5/(6 + 2.5) = 5/17

And now ,

∆mixG = nRT ( x1 in x1 + x2 in x2 )

n = n₁ + n₂ = 6 + 2.5 = 8.5 
R = 25/3 J/Kmol
T = 298K 

∆ Gmix = 8.5 × 25/3 × 298 [12/17ln(12/17) + 5/17ln(5/17)]
=12.5 × 298/3 [12ln(12/17) + 5ln(5/17) ] J 
= 12.5 × 298/3 × (-10.2985) = -12.787 kJ


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Thanks!